y=(2x-1)/(x+1) x属于3和5的闭区间的值域
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y=(2x+2-3)/(x+1)
=2(x+1)/(x+1)-3/(x+1)
=2-3/(x+1)
4<=x+1<=6
1/6<=1/(x+1)<=1/4
-3/4<=-3/(x+1)<=-1/2
2-3/4<=2-3/(x+1)<=2-1/2
值域[5/4,3/2]
=2(x+1)/(x+1)-3/(x+1)
=2-3/(x+1)
4<=x+1<=6
1/6<=1/(x+1)<=1/4
-3/4<=-3/(x+1)<=-1/2
2-3/4<=2-3/(x+1)<=2-1/2
值域[5/4,3/2]
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