化简(x+y)√(x-y/x+y)-(x-y)√(x+y/x-y)+√(1/x^2-y^2)
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解：
(x+y)√(x-y/x+y)-(x-y)√(x+y/x-y)+√(1/x^2-y^2)
=√(x+y)^2(x-y)/(x+y) -√(x-y)^2(x+y)/(x-y) +√(1-x^2y^2)/x^2
=√(x^2-y^2) - √(x^2-y^2) +√(1-x^2y^2)/x^2
=√(1-x^2y^2)/x^2
=√(1+xy)(1-xy)/x^2
(x+y)√(x-y/x+y)-(x-y)√(x+y/x-y)+√(1/x^2-y^2)
=√(x+y)^2(x-y)/(x+y) -√(x-y)^2(x+y)/(x-y) +√(1-x^2y^2)/x^2
=√(x^2-y^2) - √(x^2-y^2) +√(1-x^2y^2)/x^2
=√(1-x^2y^2)/x^2
=√(1+xy)(1-xy)/x^2
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