Question

解方程9（x-1）²=16（x+2）²

Answer 1

9（x-1）²=16（x+2）²
9（x-1）²-16（x+2）²=0
[3(x-1)-4(x+2)][3(x-1)+4(x+2)]=0
(3x-3-4x-8)(3x-3+4x+8)=0
-(x+11)(7x+5)=0
x=-11或x=-5/7

Answer 2

9（x-1）²=16（x+2）²
9（x-1）²-16（x+2）²=0
[3(x-1)-4(x+2)][3(x-1)+4(x+2)]=0
(3x-3-4x-8)(3x-3+4x+8)=0
-(x+11)(7x+5)=0
x=-11或x=-5/7 注意x不为1和-2

Answer 3

9（x-1）²=16（x+2）²
9（x-1）²-16（x+2）²=0
[3(x-1)-4(x+2)][3(x-1)+4(x+2)]=0
-(x+11)(7x+5)=0
x=-11或者x=-5/7

Answer 4

（x-1）/(x+2)=4/3然后就简单！要学会化简，还要注意分母为0的情况1

Answer 5

不知是否弄巧成拙了
9x2-18x+9=16x2+64x+64
7x2+82x+55=0
(7x+5)(x+11)=0
x1=-5/7
x2=-11