已知函数f(x)=2sin^2 (π/4+x)-根号下3倍cos2x,
已知函数f(x)=2sin^2(π/4+x)-根号下3倍cos2x,。若不等式f(x)-m=2在π/4≤x≤π/2上有解,求实数m的范围...
已知函数f(x)=2sin^2 (π/4+x)-根号下3倍cos2x,。若不等式f(x)-m=2在π/4≤x≤π/2上有解,求实数m的 范围
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f(x)=2sin^2 (π/4+x)-根号下3倍cos2x
=2sin^2 (π/4+x)-1-√3*cos2x+1
=-(1-2sin^2 (π/4+x))-√3*cos2x+1
=-cos2(π/4+x)-√3*cos2x+1
=-cos(π/2+2x)-√3*cos2x+1
=sin2x-√3*cos2x+1
=2(1/2sin2x-√3/2*cos2x)+1
=2sin(2x-π/3)+1
f(x)-m=2 m=2sin(2x-π/3)-1
sin在π/4≤x≤π/2上单调递增且为正
所以m在π/4取最小值,在π/2取最大值,带进去求出m的值即可
=2sin^2 (π/4+x)-1-√3*cos2x+1
=-(1-2sin^2 (π/4+x))-√3*cos2x+1
=-cos2(π/4+x)-√3*cos2x+1
=-cos(π/2+2x)-√3*cos2x+1
=sin2x-√3*cos2x+1
=2(1/2sin2x-√3/2*cos2x)+1
=2sin(2x-π/3)+1
f(x)-m=2 m=2sin(2x-π/3)-1
sin在π/4≤x≤π/2上单调递增且为正
所以m在π/4取最小值,在π/2取最大值,带进去求出m的值即可
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