
习题2.3 (1)x^2+12x+25=0 (2)x^2+4x=10 (3)x^2-6x=11 (4)x^2-2x-4=0
习题2.3(1)x^2+12x+25=0(2)x^2+4x=10(3)x^2-6x=11(4)x^2-2x-4=0...
习题2.3 (1)x^2+12x+25=0 (2)x^2+4x=10 (3)x^2-6x=11 (4)x^2-2x-4=0
展开
1个回答
展开全部
(1)x^2+12x+25=0
x1,2=[-12±√(12^2-4*25)]/2
=-6±√11
(2)x^2+4x=10
x^2+4x-10=0
x1,2=[-4±√(4^2-4*(-10))]/2
=-2±√14
(3)x^2-6x=11
x^2-6x-11=0
x1,2=[6±√(6^2-4*(-11))]/2
=3±2√5
(4)x^2-2x-4=0
x1,2=[2±√(2^2-4*(-4))]/2
=1±√5
x1,2=[-12±√(12^2-4*25)]/2
=-6±√11
(2)x^2+4x=10
x^2+4x-10=0
x1,2=[-4±√(4^2-4*(-10))]/2
=-2±√14
(3)x^2-6x=11
x^2-6x-11=0
x1,2=[6±√(6^2-4*(-11))]/2
=3±2√5
(4)x^2-2x-4=0
x1,2=[2±√(2^2-4*(-4))]/2
=1±√5
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询