Question

已知函数f(x)为偶函数，g(x)为奇函数，且f(x)-g(x)=x^2+x-2，则f(x)=？g(x)=?

Answer 1

f(x)-g(x)=x^2+x-2``````````````````1
f(x)=f(-x); g(x)=-g(-x)
f(-x)-g(-x)=f(x)+g(-x)=x^2-x-2````2

1+2得：2f(x)=2x^2-4
即：f(x)=x^2-2
2-1得：2g(x)=-2x
即：g(x)=-x

Answer 2

f(x)=x²-2，g（x）=-x
满意请采纳，不懂可追问，谢谢

Answer 3

Report to the boss in a letter to the boss.