急急急急!!几道小学奥数题答案
(1)1×4/1+4×7/1+7×10+…+97×100/1(2)1又1/10+2又1/40+4又1/88+6又1/154(3)(1-1/2005)+(1-1/2005×...
(1) 1×4/1+4×7/1+7×10+…+97×100/1
(2) 1又1/10+2又1/40+4又1/88+6又1/154
(3) (1-1/2005)+(1-1/2005×2)+(1-1/2005×3)+…(1-1/2005×2004) 展开
(2) 1又1/10+2又1/40+4又1/88+6又1/154
(3) (1-1/2005)+(1-1/2005×2)+(1-1/2005×3)+…(1-1/2005×2004) 展开
4个回答
展开全部
1.是否抄错题了?
应该是分子分母倒转来写了吧?
这样答案应该是:(1/3)*[(1-1/4)+(1/4-1/7)+.....+(1/97-1/100)]=(1-1/100)/3=33/100
2.13又七分之1
整数分数分别相加=13+1/10+1/40+1/88+1/154=13+1/8+1/88+1/154=13+3/22+1/154=13+1/7
3.1002
整数分数分别相加减=1*2004-(1/2005+2/2005+......+2004/2005)
=2004-2004*(1/2005+2004/2005)/2=2004-1002=1002
应该是分子分母倒转来写了吧?
这样答案应该是:(1/3)*[(1-1/4)+(1/4-1/7)+.....+(1/97-1/100)]=(1-1/100)/3=33/100
2.13又七分之1
整数分数分别相加=13+1/10+1/40+1/88+1/154=13+1/8+1/88+1/154=13+3/22+1/154=13+1/7
3.1002
整数分数分别相加减=1*2004-(1/2005+2/2005+......+2004/2005)
=2004-2004*(1/2005+2004/2005)/2=2004-1002=1002
展开全部
(1)=1/3×(1-1/4)+1/3×(1/4-1/7)+……+1/3×(1/97-1/100)
=1/3×(1-1/4+1/4-1/7+……+1/97-1/100)
=1/3×(1-1/100)
=33/100
第2题把分母变成是10 40 88 154的公倍数然后再相加
(3)
1-1/2^2=(1-1/2)*(1+1/2)=1/2*3/2
(1-1/2^2)(1-1/3^2)(1-1/4^2)......(1-1/2004^2)(1-1/2005^2)
=(1/2)*(3/2)*(2/3)*(4/3)*(3/4)*(5/4)*(4/5).......(2004/2005)*(2006/2005)
=1/2*(2006/2005)
=1003/2005
=1/3×(1-1/4+1/4-1/7+……+1/97-1/100)
=1/3×(1-1/100)
=33/100
第2题把分母变成是10 40 88 154的公倍数然后再相加
(3)
1-1/2^2=(1-1/2)*(1+1/2)=1/2*3/2
(1-1/2^2)(1-1/3^2)(1-1/4^2)......(1-1/2004^2)(1-1/2005^2)
=(1/2)*(3/2)*(2/3)*(4/3)*(3/4)*(5/4)*(4/5).......(2004/2005)*(2006/2005)
=1/2*(2006/2005)
=1003/2005
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询