求把下面的mathematica改写成matlab,并得出结果
Integrate[1/(2\[Pi])*\[Gamma]\[Lambda]^2/((l-d-\[Omega])^2+\[Lambda]^2)*E^(-I*\[Omega...
Integrate[
1/(2 \[Pi])*\[Gamma]\[Lambda]^2/((l - d - \[Omega])^2 + \[Lambda]^2)*
E^(-I*\[Omega]*t), {\[Omega], 0, Infinity}] 展开
1/(2 \[Pi])*\[Gamma]\[Lambda]^2/((l - d - \[Omega])^2 + \[Lambda]^2)*
E^(-I*\[Omega]*t), {\[Omega], 0, Infinity}] 展开
展开全部
int( 1/(2*pi)*Ga*La^2/((I- d - x)^2 + La^2)* E^(-I*x*t), x, 0, Inf)
没有解析解
syms Ga La I d x E t
int( 1/(2*pi)*Ga*La^2/((I - d - x)^2 + La^2)* E^(-I*x*t), x, 0, Inf)
Warning: Explicit integral could not be found.
ans =
int((5734161139222659*Ga*La^2)/(36028797018963968*E^(I*t*x)*((d - I + x)^2 + La^2)), x = 0..Inf)
没有解析解
syms Ga La I d x E t
int( 1/(2*pi)*Ga*La^2/((I - d - x)^2 + La^2)* E^(-I*x*t), x, 0, Inf)
Warning: Explicit integral could not be found.
ans =
int((5734161139222659*Ga*La^2)/(36028797018963968*E^(I*t*x)*((d - I + x)^2 + La^2)), x = 0..Inf)
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谢谢~~~
追答
你如果要求值的话考虑带入参数 算数值积分
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