Question

数据结构作业 用c语言建立一个存储学生数据的单链表 链表中节点数据域由学号年龄成绩构成

382795867@qq.com
最好要exe文件

Answer 1

#include<stdio.h>
#include<ctype.h>
#include<stdlib.h>

int main(void)
{
struct student
{
int age;
double score;
char name[20];
char studentNumber[20;]

struct student *next;

};

struct student *first=NULL;
struct student *current=NULL;
struct student *last=NULL;

char test='\0';

for( ; ; )
{

printf(" (Y=继续 or N=取消)?");
scanf(" %c",&test);
if(tolower(test)=='n')
break;

current=(struct student*) malloc (sizeof (struct student) );

if(first==NULL)
{
first=current;

}

else
{
last->next=current;

}

printf("\n student Name（输入学生姓名） :");
scanf("%s",current->name);
printf("\n student Name（输入学生学号） :");
scanf("%s",current->studentNumber);

printf("\n student age（学生年龄）:");
scanf("%d",¤t->age);

printf("\nstudent score（分数）:");
scanf("%ld",¤t->score);
current->next=NULL;

last=current;
}

printf(" \n \n \t");
printf("姓名 学号 年龄 分数 " );
current=first;
while(current!=NULL)
{
printf("\t--------------------------------\n");
printf("\t%-s %10s %5d %5.2ld \n",
current->name,current->studentNumber,
current->age,current->score);

last=current;
current=current->next;

free(last);
}
return(0);
}

Answer 2

写得很好