Question

c++外部类中在构造函数时如何给内部类属性赋值？

#include<iostream.h>
#include<string.h>
class Money
{
private:
float ammount;
public:
Money(float a=0): amount(a)
{}
};
class Account
{
private:
long accountNo;
char name[30];
Money remains;
public:
Account(long a=0,char *n==NULL,Money m):
account(a),remains(m)
{
strcpy(name,n);
}
};
如何在class Account 的构造函数中给 remains 赋初值？？？

Answer 1

#include<iostream.h>
#include<string.h>
class Money
{
private:
float amount;
public:
Money(Money &m){ this->amount = m.amount ;}
Money(float a=0): amount(a){}
};
class Account
{
private:
long accountNo;
char name[30];
Money remains;
public:
Account(long a=0,char *n=NULL,Money m):accountNo(a),remains(m){
strcpy(name,n);
}
};
加个拷贝构造函数给Money

Answer 2

你写对了啊，就是这样写，
Account(long a=0,char *n==NULL,Money m): account(a),remains(m)
{
strcpy(name,n);
}

Answer 3

你自己已经写出来了，还问什么？