Question

求C语言这道题目的代码!

5.战争年代，电报的传输，一般不会直接传输，都会加密！我们完成一个程序，
实现对26个字母的加密

明文：a b c d e f g h i j k l m n o p q r s t u v w x y z
密文：d e f g h i j k l m n o p q r s t u v w x y z a b c
要求大家输入任意一个字母，对应他的密文！

Answer 1

#include <stdio.h>

char DeCoder(char arg) {
if (arg <= 'w' && arg >= 'a' ) //若是a到w
{
return arg + 3; //按ANSI码向后偏移3位
}
else if (arg >= 'x' && arg <= 'z') //若是x,y,z
{
return arg - 23; //按ANSI码向前偏移23位
}
return 0;
}

int main()
{
for (char i = 'a';i <='z';i++) //从明码a到z遍历
{
printf("%c ",DeCoder(i)); //输出暗码

}
printf("\n");
return 0;
}

采纳吧，LZ。

Answer 2

/*
明文：a b c d e f g h i j k l m n o p q r s t u v w x y z
密文：d e f g h i j k l m n o p q r s t u v w x y z a b c
*/

#include <stdio.h>

char encrypt(char ch)
{
char tmp;

if(ch>='a'&&ch<='z')
{
tmp = (ch<='w')? (ch+3) : (ch-23);
}
else if(ch>='A'&&ch<='Z')
{
tmp = (ch<='W')? (ch+3) : (ch-23);
}
else
{
tmp = ch;
}

return tmp;
}

int main(void)
{
char ch='a';

for(ch='a';ch<='z';ch++) { printf("%c ",ch); }

printf("\n");

for(ch='a';ch<='z';ch++) { printf("%c ",encrypt(ch)); }

printf("\n==============================================\n");

while(1)
{
ch = getchar();
printf("%c",encrypt(ch));
}

getchar();
return 0;
}

Answer 3

/* Note:Your choice is C IDE */
#include "stdio.h"
void main()
{
void translate(char *p1,char *p2);
char ch[100],result[100];
scanf("%s",ch);
translate(ch,result);
printf("\n");
printf("%s\n%s\n",ch,result);

}
void translate(char *p1,char *p2)
{
while(*p1!='\0')
{
if(*p1>='a'&&*p1<='w') *p2=*p1+3;

else if(*p1=='x') *p2='a';
else if(*p1=='y') *p2='b';
else if(*p1=='z') *p2='c';
p1++;p2++;
}
*p2='\0';
}

Answer 4

#include <stdio>

int main()
{
char ciphertext;

scanf("%c", &ciphertext);

if (ciphertext >= 'a' && ciphertext <= 'z') {
if (ciphertext <= 'w') {
ciphertext += 3;
}
else {
ciphertext -= 23;
}
}

printf("%c", ciphertext);
}

Answer 5

#include <stdio.h>
main()
{
char c;
scanf("%c",&c);
c=c+3<='z'?c+3:c+3-26;
printf("%c\n",c);
}