(3-2根号2)x²+2(根号2-1)x-1=0 解方程 跪求谢谢各位啦~~~急死人了
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(3-2√2)x^2 + 2(√2-1)*x -1 = 0
(2-2√2+1)x^2 + 2(√2-1)*x -1 = 0
(√2-1)^2*x^2 + 2(√2-1)*x -1 = 0
((√迹带2-1)*x)^2 + 2(√2-1)*x -1 = 0
((√桥则2-1)*x )^2+ 2(√2-1)*x +1= 2
((√2-1)*x+1)^2 = 2
(√2-1)*x+1 = √2 或 -√2
x = 1，或姿消芦 -√2/2
(2-2√2+1)x^2 + 2(√2-1)*x -1 = 0
(√2-1)^2*x^2 + 2(√2-1)*x -1 = 0
((√迹带2-1)*x)^2 + 2(√2-1)*x -1 = 0
((√桥则2-1)*x )^2+ 2(√2-1)*x +1= 2
((√2-1)*x+1)^2 = 2
(√2-1)*x+1 = √2 或 -√2
x = 1，或姿消芦 -√2/2
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