Question

c语言小白求解释，两个问题

1.The value of expression (z=0) && (x=2)||(z=1) is_______。
2.#include <stdio.h>
void main( )
{ int y;
double d=3.4, x;
x=(y=d/2.0)/2;
printf(" (%0.2f, %d) ", x, y);
}
X,Y分别为
希望大牛帮小弟解决，并解释

Answer 1

1. 1 (z = 0) && (x = 2) 为假 表达式为 0 0||(z = 1) 表达式为 非零 是 1
2. int y = (int ) (d/2.0) = (int)(3.4/2.0) = (int) 1.7 = 1
double x = (double) 1 = 1.00000000
printf的结果 为 1.00 1

Answer 2

1. 1
2. x = 0 y = 1

Answer 3

1. 1
2. x = 0 y = 1

Answer 4

1. 1
2. int y = (int ) (d/2.0) = (int)(3.4/2.0) = (int) 1.7 = 1
double x = (double) （1/2=0） = 0.000000
printf的结果 为 0.00 1