Question

在正方形ABCD中，点P在CD上，连接PA，分别过点B、D作BE⊥PA、DF⊥PA，垂足分别为E、F

（1）求证BE=DF+EF
（2）当点P在CD的延长线上时，其他条件不变，试探索BE,DF,EF之间有怎样的数量关系，且证明

Answer 1

(1)∵正方形ABCD∴AB=AD，角BAD=90°∵BE⊥PA∴角BAE=90°∵DF⊥PA∴角AFD=90°∴角BAE=角AFD∵角BAD=90°∴角BAE+角FAD=90°∵在△ABE中，BAE=90°∴角abe+角bae=90°∴角abe=角FAD然后证abe和dae全等，再然后你应该会了 （2）ef=be+df,先证全等就行了

Answer 2

正方形

Answer 3

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Answer 4

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