Question

python怎么把re中的findall（）找出来存在文件里

# -*- coding: utf -8 -*-
import urllib
import urllib2
import re
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
values = {'name' : 'WHY',
'location' : 'SDU',
'language' : 'Python' }

headers = { 'User-Agent' : user_agent }
data = urllib.urlencode(values)

request = urllib2.Request('http://search.jiayuan.com/',data,headers)
request.add_header('User-Agent', 'fake-client')
response = urllib2.urlopen(request)
data1 = response.read()
#file1 = open('test1.txt', 'w')
#file1.write(data1)
r=re.compile(r"var normal_user.*\n.*;")
s=r.findall(data1)

后面想要在s里面再用正则表达式搜索一下，更精确查找。但是s是一个list，不是个字符串··怎么才变字符串···

求大神····

Answer 1

个人观点: 用分行保存更方便进一步处理

with open('tmp_parsered.txt', 'wt') as handle:
handle.write( '\n'.join(r.findall(data1)) )

Answer 2

data1 = ''.join(data1) ,这样就ok了

Answer 3

s2=''.join(s)
#然后再对s2用正则即可