Question

已知函数f(x)=2sin(2x+π/6)+a+1（其中a为常数)

（1）求f(x)的最小正周期（2）若x属于[0,π/2]时f(x)最大值是4，求a(3)求出使F(x)取最大值时x的取值集合

Answer 1

1,T=2π/2=π
2,f(x)最大2+a+1=4,a=1
3,2x+π/6=2kπ+π/2,x=kπ+π/6

Answer 2

最小正周期为π，a为1，x=π/6+kπ

Answer 3

(1)T=2π/2=π