Question

c++的一道题显示错误为 error C2676

#include<iostream>
#include<string>
using namespace std;
struct student
{
int num;
string name;
float score[3];
}stu[5];
void input(student &stu)
{
int i,k;
for (i=0;i<5;i++)
{
cin>>stu[i].num>>stu[i].name;
for(k=0;k<3;k++)
cin>>stu[i].score[k];
}}

void print(student stu)
{
int k;
cout<<stu.num<<" "<<stu.name<<" ";
for(k=0;k<3;k++)
{cout<<stu.score[k]<<" ";}
cout<<endl;
}

int main()
{
int i;
for (i=0;i<5;i++)
{
input(stu[i]);
print(stu[i]);}
return 0;
}
错误显示为：
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(15) : error C2676: binary '[' : 'struct student' does not define this operator or a conversion to a type acceptable to the predefined operator
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(15) : error C2228: left of '.num' must have class/struct/union type
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(15) : error C2676: binary '[' : 'struct student' does not define this operator or a conversion to a type acceptable to the predefined operator
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(15) : error C2228: left of '.name' must have class/struct/union type
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(17) : error C2676: binary '[' : 'struct student' does not define this operator or a conversion to a type acceptable to the predefined operator
C:\Users\SAMSUNG\Desktop\文件夹\资料\应用程序\3.cpp(17) : error C2228: left of '.score' must have class/struct/union type
执行 cl.exe 时出错.

Answer 1

#include<iostream>
#include<string>
using namespace std;

typedef struct student
{
int num;
string name;
float score[3];
}stu;
void input(student &stu)
{

cin >> stu.num >> stu.name;
for (int k = 0; k < 3; k++)
cin >> stu.score[k];

}

void print(student stu)
{
cout << stu.num << " " << stu.name << " ";
for (int k = 0; k < 3; k++)
{
cout << stu.score[k] << " ";
}
cout << endl;
}

int main()
{
stu s[5];
int i;
for (i = 0; i < 5; i++)
{
input(s[i]);
print(s[i]);
}
return 0;
}

Answer 2

void input(student &stu)
{
int i,k;
cin>>stu.num>>stu.name;
for(k=0;k<3;k++)
{
cin>>stu.score[k];
}
}

Answer 3

编译器错误 C2676
　　错误消息:
　　二元“operator”:“type”不定义此运算符或到预定义运算符可接收的类型的转换
　　若要使用该运算符，必须针对指定类型将其重载，或者定义一个到某个类型（该运算符已针对此类型进行了定义）的转换。
更多的编译器错误查询：
http://msdn.microsoft.com/zh-cn/library/sah8k6f4.aspx