已知x-y/xy=3,求分式2x+3xy-2y/x-2xy-y的值.
2个回答
展开全部
(x-y)/xy=3
1/y-1/x=3
(2x+3xy-2y)/(x-2xy-y)
=(2/y+3-2/x)/(1/y-2-1/x)…………这一步分子分母同除以xy
=[3+2(1/y-1/x)]/[-2+(1/y-1/x)]
=(3+2×3)/(-2+3)
=9
1/y-1/x=3
(2x+3xy-2y)/(x-2xy-y)
=(2/y+3-2/x)/(1/y-2-1/x)…………这一步分子分母同除以xy
=[3+2(1/y-1/x)]/[-2+(1/y-1/x)]
=(3+2×3)/(-2+3)
=9
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
∵x-y/xy=3
∴x-y=3xy
2x+3xy-2y/x-2xy-y
=[2(x-y)+3xy]/[(x-y)-2xy]
=(6xy+3xy)/(3xy-2xy)
=9xy/(xy)
=9
∴x-y=3xy
2x+3xy-2y/x-2xy-y
=[2(x-y)+3xy]/[(x-y)-2xy]
=(6xy+3xy)/(3xy-2xy)
=9xy/(xy)
=9
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询