若不等式 的正整数解是1、2,则m的取值范围是 。
若不等式的正整数解是1、2,则m的取值范围是。...
若不等式 的正整数解是1、2,则m的取值范围是 。
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小小财861
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试题分析:解不等式 ![](https://iknow-pic.cdn.bcebos.com/cdbf6c81800a19d87a5d52b430fa828ba61e4621?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) 得 ![](https://iknow-pic.cdn.bcebos.com/8cb1cb134954092366d5b5cf9158d109b2de49c7?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) ,再根据不等式 ![](https://iknow-pic.cdn.bcebos.com/cdbf6c81800a19d87a5d52b430fa828ba61e4621?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) 的正整数解是1、2求解即可. 解不等式 ![](https://iknow-pic.cdn.bcebos.com/cdbf6c81800a19d87a5d52b430fa828ba61e4621?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) 得 因为不等式 ![](https://iknow-pic.cdn.bcebos.com/cdbf6c81800a19d87a5d52b430fa828ba61e4621?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) 的正整数解是1、2 所有 ![](https://iknow-pic.cdn.bcebos.com/bd3eb13533fa828b6c7d4b52fe1f4134970a5a21?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) ,解得 ![](https://iknow-pic.cdn.bcebos.com/0823dd54564e92586f88505f9f82d158cdbf4ec7?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto) . 点评:本题属于基础应用题,只需学生熟练掌握不等式的解集的特征,即可完成. |
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