
初二数学计算题(要过程,谢谢!)(1)(3/2)^-3*(-0.25)^0+3^-3
(1)(3/2)^-3*(-0.25)^0+3^-3(2)2^-1-(3.14-π)^0-(-1)^3(3)(3/2)^-1*(π-2)^0-(-3/2)^2÷(2/3)...
(1)(3/2)^-3*(-0.25)^0+3^-3
( 2 ) 2^-1-(3.14-π)^0-(-1)^3
(3)(3/2)^-1*(π-2)^0-(-3/2)^2÷(2/3)^-3 展开
( 2 ) 2^-1-(3.14-π)^0-(-1)^3
(3)(3/2)^-1*(π-2)^0-(-3/2)^2÷(2/3)^-3 展开
1个回答
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(3/2)^-3 × (-0.25)^0 + 3^-3
= 8/27 × 1 + 1/27
= 9/27
= 1/3
(2) 2^-1 - ( 3.14 - π)^0 - ( -1)^3
= 1/2 - 1 + 1
= 1/2
(3) (3/2)^-1 × (π - 2)^0 - ( -3/2)^2 ÷ (2/3)^-3
= 2/3 × 1 - 9/4 ÷ 27/8
= 2/3 - 9/4 × 8/27
= 2/3 - 2/3
= 0
= 8/27 × 1 + 1/27
= 9/27
= 1/3
(2) 2^-1 - ( 3.14 - π)^0 - ( -1)^3
= 1/2 - 1 + 1
= 1/2
(3) (3/2)^-1 × (π - 2)^0 - ( -3/2)^2 ÷ (2/3)^-3
= 2/3 × 1 - 9/4 ÷ 27/8
= 2/3 - 9/4 × 8/27
= 2/3 - 2/3
= 0
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