(xx-1)(x+3)(x+5)-9怎样因式分解
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(x²-1)(x+3)(x+5)-9
= (x+1)(x-1)(x+3)(x+5)-9
= {(x+1)(x+3)}{(x-1)(x+5)}-9
= {x²+4x+3}{x²+4x-5}-9
= (x²+4x)²-2(x²+4x)-15-9
= (x²+4x)²-2(x²+4x)-24
= (x²+4x+4)(x²+4x-6)
= (x+2)²(x+2+√10)(x+2-√10)
= (x+1)(x-1)(x+3)(x+5)-9
= {(x+1)(x+3)}{(x-1)(x+5)}-9
= {x²+4x+3}{x²+4x-5}-9
= (x²+4x)²-2(x²+4x)-15-9
= (x²+4x)²-2(x²+4x)-24
= (x²+4x+4)(x²+4x-6)
= (x+2)²(x+2+√10)(x+2-√10)
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