quick-cocos2d-x想制作一个退出游戏的按钮,怎么实现
1个回答
推荐于2016-02-04
展开全部
function MainScene:addBackEvent()
if device.platform == "android" then
self.touchLayer = display.newLayer()
self.touchLayer:addNodeEventListener(cc.KEYPAD_EVENT, function(event)
if event.key == "back" then
--CCDirector:sharedDirector():endToLua()
local javaClassName = "com/cocos2dx/testgame/Testgame"
local javaMethodName = "exit"
luaj.callStaticMethod(javaClassName, javaMethodName)
end
end)
self.touchLayer:setKeypadEnabled(true)
self:addChild(self.touchLayer)
end
end
if device.platform == "android" then
self.touchLayer = display.newLayer()
self.touchLayer:addNodeEventListener(cc.KEYPAD_EVENT, function(event)
if event.key == "back" then
--CCDirector:sharedDirector():endToLua()
local javaClassName = "com/cocos2dx/testgame/Testgame"
local javaMethodName = "exit"
luaj.callStaticMethod(javaClassName, javaMethodName)
end
end)
self.touchLayer:setKeypadEnabled(true)
self:addChild(self.touchLayer)
end
end
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询