
数学简单线性规划问题!急急!!! 20
已知实数x,y满足(x-y+6)*(x+y-6)大于等于零,且x大于等于1小于等于4,则x^2+y^2-2的取值范围是?...
已知实数x,y满足(x-y+6)*(x+y-6)大于等于零,且x大于等于1小于等于4,则x^2+y^2-2的取值范围是?
展开
1个回答
展开全部
(x-y+6)*(x+y-6)=x方-(y-6)方.
1=<x<=4 则 1<=(y-6)方<=16 -4<=y-6<=-1 或 1<=y-6<=4
2<=y<=5 或 7<=y<=10
则 1<=x方<=16 4<=y方<=25 或 49<=y方<=100
则 x^2+y^2-2的取值范围是 [3,39] 或 [48,114].
1=<x<=4 则 1<=(y-6)方<=16 -4<=y-6<=-1 或 1<=y-6<=4
2<=y<=5 或 7<=y<=10
则 1<=x方<=16 4<=y方<=25 或 49<=y方<=100
则 x^2+y^2-2的取值范围是 [3,39] 或 [48,114].
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询