几道脱式计算！（能简算可以简算）
4/5×1/3+2/5÷0.6-1/15=====99×（1/3+1/11+1/9)=====[1-（4又1/3-1又3/4×2）]÷2又1/2=====（1又5/8+1...
4/5×1/3+2/5÷0.6-1/15
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99×（1/3+1/11+1/9)
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[1-（4又1/3-1又3/4×2）]÷2又1/2
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（1又5/8+1/4）÷（3/4×2又2/3-1又1/2）
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99×（1/3+1/11+1/9)
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[1-（4又1/3-1又3/4×2）]÷2又1/2
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（1又5/8+1/4）÷（3/4×2又2/3-1又1/2）
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1个回答
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4/5×1/3+2/5÷0.6-1/15
=4/15-1/15+2/5×5/3
=1/5+2/3
=13/15
99×（1/3+1/11+1/9)
=99×1/3+99×1/11+99×1/9
=33+9+11
=53
[1-（4又1/3-1又3/4×2）]÷2又1/2
=[1-4-1/3-2-3/2]×2/5
=-6×2/5-5/6×2/5
=-12/5-1/3
=-2又11/15
（1又5/8+1/4）÷（3/4×2又2/3-1又1/2）
=(13/8+1/4)×2
=13/8×2+1/4×2
=13/4+1/2
=3又3/4
=4/15-1/15+2/5×5/3
=1/5+2/3
=13/15
99×（1/3+1/11+1/9)
=99×1/3+99×1/11+99×1/9
=33+9+11
=53
[1-（4又1/3-1又3/4×2）]÷2又1/2
=[1-4-1/3-2-3/2]×2/5
=-6×2/5-5/6×2/5
=-12/5-1/3
=-2又11/15
（1又5/8+1/4）÷（3/4×2又2/3-1又1/2）
=(13/8+1/4)×2
=13/8×2+1/4×2
=13/4+1/2
=3又3/4
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