提取公因式发分解因式a(a-b)+b(b-a)
展开全部
a(a-b)+b(b-a)
=(a-b)(a-b)
=(a-b)²
=(a-b)(a-b)
=(a-b)²
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
80a^2(a+b)-45b^2(a+b)
=(a+b)(80a^2-45b^2)
=(a+b)5(16a^2-9b^2)
=(a+b)5( <4a>^2-<3b>^2)
=(a+b)5( 4a-3b)( 4a+3b)
=5(a+b)( 4a-3b)( 4a+3b)
-2(m-n)^2+32
=-2<(m-n)^2-16>
=-2<(m-n)^2-4^2>
=-2<(m-n-4)(m-n+4)>
a^2(x-y)+b^2(y-x)
=a^2(x-y)-b^2(x-y)
=(x-y)(a^2-b^2 )
=(x-y)(a-b)(a+b)
25(m+n+2)^2-16(m-n-2)^2
=<5(m+n+2)>^2-<卜森4(m-n-2)>^2
=<拆弊汪5(m+n+2)-4(m-n-2)>*<5(m+n+2)+4(m-n-2)>旅仔*
=(m+9n+18)*(9m-n-6)
=(a+b)(80a^2-45b^2)
=(a+b)5(16a^2-9b^2)
=(a+b)5( <4a>^2-<3b>^2)
=(a+b)5( 4a-3b)( 4a+3b)
=5(a+b)( 4a-3b)( 4a+3b)
-2(m-n)^2+32
=-2<(m-n)^2-16>
=-2<(m-n)^2-4^2>
=-2<(m-n-4)(m-n+4)>
a^2(x-y)+b^2(y-x)
=a^2(x-y)-b^2(x-y)
=(x-y)(a^2-b^2 )
=(x-y)(a-b)(a+b)
25(m+n+2)^2-16(m-n-2)^2
=<5(m+n+2)>^2-<卜森4(m-n-2)>^2
=<拆弊汪5(m+n+2)-4(m-n-2)>*<5(m+n+2)+4(m-n-2)>旅仔*
=(m+9n+18)*(9m-n-6)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询