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根据题意a+2=0,a+b+5=0,解得a=-2,b=-3
3a^2b-[2a^2b-(3ab-a^2-4a^2)]-2ab
=3a^2b-2a^2b+(3ab-a^2-4a^2)-2ab
=a^2b+ab-5a^2
=4*(-3)+(-2)(-3)-5*4
=-12+6-20
=-26
3a^2b-[2a^2b-(3ab-a^2-4a^2)]-2ab
=3a^2b-2a^2b+(3ab-a^2-4a^2)-2ab
=a^2b+ab-5a^2
=4*(-3)+(-2)(-3)-5*4
=-12+6-20
=-26
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