
当x趋向于0时,(1+sinx)^1/sin2x的极限
2个回答
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lim(x→0)(1+sinx)^1/sin2x
=lim(x→0)(1+sinx)^1/(2sinxcosx)
=lim(x→0)(1+sinx)^1/(2sinx)
=lim(x→0)[(1+sinx)^1/(sinx)]^(1/2)
=e^(1/2)
=lim(x→0)(1+sinx)^1/(2sinxcosx)
=lim(x→0)(1+sinx)^1/(2sinx)
=lim(x→0)[(1+sinx)^1/(sinx)]^(1/2)
=e^(1/2)
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