Question

已知|a+2|+(b+3)^2=0,求3a^2b-【2a^2b-(2ab-a^2)-4a^2】-ab的值

Answer 1

绝对值和平方大于等于0，相加等于0，若有一个大于0，则另一个小于0，不成立。
所以两个都等于0
所以a+2=0,b+3=0
a=-2,b=-3
所以原式=3a²b-2a²b+2ab-a²+4a²-ab
=a²b+ab-3a²
=-12+6-27
=-39

Answer 2

所以两个都等于0
所以a+2=0,b+3=0
a=-2,b=-3
所以原式=3a²b-2a²b+2ab-a²+4a²-ab
=a²b+ab-3a²
=-12+6-27

Answer 3

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