Question

下列程序的错误提示为:(在VC++6.0中运行)error C2660: 'area' : function does not take 0 parameters

#include<iostream.h>
class Rectangle
{
public:
Rectangle(int a,int b);
int area(int a,int b);
private:
int chang,kuan;
};
int Rectangle::area(int a,int b)
{
chang=a;
kuan=b;
return chang*kuan;
}
int main()
{
int mianji,a,b;
cin>>a;
cin>>b;
Rectangle s(a,b);
mianji=s.area();
cout<<"mianji="<<mianji<<endl;
return 0;
}上述程序的错误提示为:(在VC++6.0中运行)error C2660: 'area' : function does not take 0 parameters

请问是哪里错了?帮忙纠正,谢谢

Answer 1

int area(int a,int b);
你定义的area有两个参数，
但
mianji=s.area();
使用时，一个参数都没有传递。

修改使其相匹配。

追问

请将正确的给我发过来,谢谢

追答

#include
class Rectangle
{
public:
Rectangle(int a,int b);
int area(int a,int b);
private:
int chang,kuan;
};
int Rectangle::area(int a,int b)
{
chang=a;
kuan=b;
return chang*kuan;
}
int main()
{
int mianji,a,b;
cin>>a;
cin>>b;
Rectangle s(a,b);
mianji=s.area(a,b); // //
cout<<"mianji="<<mianji<<endl;
return 0;
}

Answer 2

int Rectangle::area(int a,int b)
你没输入参数，怎么计算。
如果想要默认参数，再写一个
int Rectangle::area()
{
return chang*kuan;
}

Answer 3

int main()
{
int mianji,a,b;
cin>>a;
cin>>b;
Rectangle s(a,b);
mianji=s.area(a,b);
cout<<"mianji="<<mianji<<endl;
return 0;
}

Answer 4

#include<iostream.h>

class Rectangle
{
public:
Rectangle(int a,int b);
int area();
int area(int a,int b);
private:
int chang,kuan;
};

// 含参构造函数需要自己实现
Rectangle::Rectangle(int a,int b)
{
chang = a;
kuan = b;
}

int Rectangle::area()
{
return chang * kuan;
}

int Rectangle::area(int a,int b)
{
chang=a;
kuan=b;
return chang*kuan;
}

int main()
{
int mianji,a,b;
cin>>a;
cin>>b;
Rectangle s(a,b);
mianji=s.area();
cout<<"mianji="<<mianji<<endl;
return 0;
}

Answer 5

。。。。。。。。。。。。。。