Question

a(a+1)(a+2)(a+3)+1用因式分解法作！！！！！详细！！！！！

Answer 1

a(a+1)(a+2)(a+3)+1
=（a²+3a）（a²+3a+2）+1
=（a²+3a）²+2（a²+3a）+1
=（a²+3a+1）²

Answer 2

a(a+1)(a+2)(a+3)+1
=[a(a+3)][(a+1)(a+2)]+1
=(a²+3a)(a²+3a+2)+1
=[(a²+3a+2)-2](a²+3a+2)+1
=(a²+3a+2)²-2(a²+3a+2)+1
=[(a²+3a+2)-1]²
=(a²+3a+1)²