1个回答
2017-10-27
展开全部
z=f(x^2,g(y/x))
az/ax=f`1(2x)+f`2g`(y/x)(-y/x²)
=2xf`1-y/x²f`2 g`(y/x)
a^2z/axay
=2x[f``11*0+f``12g`(y/x)(1/x)]-{1/x²f`2g`(y/x)+y/x²g`(y/x)[f``12*0+f``22g`(y/x)/x]+y/x²f`2g``(y/x)/x}
=2x[f``12g`(y/x)(1/x)]-{1/x²f`2g`(y/x)+y/x²g`(y/x)[f``22g`(y/x)/x]+y/x²f`2g``(y/x)/x}
az/ax=f`1(2x)+f`2g`(y/x)(-y/x²)
=2xf`1-y/x²f`2 g`(y/x)
a^2z/axay
=2x[f``11*0+f``12g`(y/x)(1/x)]-{1/x²f`2g`(y/x)+y/x²g`(y/x)[f``12*0+f``22g`(y/x)/x]+y/x²f`2g``(y/x)/x}
=2x[f``12g`(y/x)(1/x)]-{1/x²f`2g`(y/x)+y/x²g`(y/x)[f``22g`(y/x)/x]+y/x²f`2g``(y/x)/x}
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谢谢大神,谢谢!!
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