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请问这两道题怎么做,谢谢
3个回答
展开全部
解:x²-2x+1-13=0
(x-1)²=13
x-1=±根号13
x=1±根号13
2x²-4x-1=0
2(x²-2x+1)-1=0
(x-1)²=1/2
x-1=±根号1/2
x=1±根号1/2
(x-1)²=13
x-1=±根号13
x=1±根号13
2x²-4x-1=0
2(x²-2x+1)-1=0
(x-1)²=1/2
x-1=±根号1/2
x=1±根号1/2
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