Question

已知m的二次方+m-11=0，试求m的三次方+12xm的二次方加2012的值

Answer 1

因为 m²+m-11=0
所以
m²+m=11
m的三次方+12m²+2012
=m^3+m^2+11m^2+2012
=m(m^2+m)+11m^2+2012
=11m+11m^2+2012
=11*(m^2+m)+2012
=11*11+2012
=2012+121
=2133

Answer 2

m的三次方+12xm的二次方加2012
=m³+m²-11m+11m²+11m-121+2133
=m(m²+m-11)+11(m²+m-11)+2133
=2133