Question

求教bat循环查找文件夹，并输出路径替换字符串

希望实现：文本中内容（ABC每行一个）ABC当前目录结构：111---11-----A 222---22-----B 333---33-----3------C------A 444---D 555---B只要包含 ABC中任意一个或多个就输出 并 跳出 到下一个文件中查找输出结果：111\11222\22333\33\3555for /f "delims=" %%f in ('dir /ad /on /b') do ( if "%%f" NEQ "Target folder" ( set next_file="no" set find_path=!file_path!%%f\ for /f "delims=" %%x in (aa.txt) do ( if !next_file! == "no" ( set have_be_fount="no" set find_file=%%x for /f "delims=" %%f in ('dir /ad /b /s "%find_path%""%find_file%"') do ( if !have_be_fount! == "no" ( set temp="%%f" echo !temp! | find "!find_file!">nul&&set copy_path=!temp! if "!copy_path!" NEQ "" ( SET copy_path=!copy_path:%find_file%=! echo be_copy_path: !copy_path! set next_file="go" set have_be_fount="yes" ) ) ) ) ) ))goto OUT

Answer 1

硬是没看明白什么意思？？？