Question

VC++6.0下运行出错 就这行-Person leader[3]={"li",0,"zhang",0,"fun",0}; 怎样修改？？

#include <iostream>
#include <string>
using namespace std;
struct Person
{
string name;
int count;
};
int main()
{
Person leader[3]={"li",0,"zhang",0,"fun",0};
int i,j;
string leader_name;
for(i=0;i<10;i++)
{
cin>>leader_name;
for(j=0;j<3;j++)
{if(leader_name==leader[j].name ) leader[j].count ++; }
}
cout<<endl;
for(i=0;i<3;i++)
cout<<leader[i].name<<".count is"<<leader[i].count <<endl;
return 0;
}

Answer 1

改成
Person leader[3]={{"li",0},{"zhang",0},{"fun",0}};
可在VS2010上编译通过
在VC++6.0上报错是因为VC++6.0不能对包含string成员的结构体变量初始化
两种解决方法
一、用char数组替换string
二、单个赋值，如
leader[0].name="li";
leader[1].name="zhang";
leader[2].name="fun";
.....

追问

书上给的就是这句 有些C++系统不能对包含string成员的结构体变量初始化
需要修改才能运行
前一个例子就是用char 但是有点浪费内存空间

只能单个赋值 没有其他改法了么？？

追答

#include
#include
using namespace std;
struct Person
{
string name;
int count;
Person(string n, int c) {name = n; count = c;};//加个构造函数
};
int main()
{
Person leader[3]={
Person("li",0), //用构造函数初始化
Person("zhang",0), //同上
Person("fun",0) //同上
};
int i,j;
string leader_name;
for(i=0;i>leader_name;
for(j=0;j<3;j++)
{if(leader_name==leader[j].name ) leader[j].count ++; }
}
cout<<endl;
for(i=0;i<3;i++)
cout<<leader[i].name<<".count is"<<leader[i].count <<endl;
return 0;
}

Answer 2

Person leader[3]={{"li",0},{"zhang",0},{"fun",0}};

Answer 3

Person leader[3]={"li",0,"zhang",0,"fun",0};
修改成
struct Person leader[3]={"li",0,"zhang",0,"fun",0};
试试，
若不行，将错误代码贴上来，方便查找错误原因

追问

: error C2440: 'initializing' : cannot convert from 'const int' to 'struct Person'
No constructor could take the source type, or constructor overload resolution was ambiguous
: error C2440: 'initializing' : cannot convert from 'char [6]' to 'struct Person'
liqi2_01.exe - 1 error(s), 0 warning(s)

有些C++系统不能对包含string成员的结构体变量初始化

Answer 4

一楼回答正确
Person leader[3]={{"li",0},{"zhang",0},{"fun",0}};
结构体数组初始化时对于每成员应该用｛｝分开