Question

已知a^2+2ab+b^2=0,求代数式a(a+4b)-(a+2b)(a-2b)的值

如题，谢了

Answer 1

a^2+2ab+b^2=0
(a+b)²=0
a+b=0

a(a+4b)-(a+2b)(a-2b)
=a²+4ab-(a²-4b²)
=4ab+4b²
=4b(a+b)
=0

Answer 2

a^2+2ab+b^2=0
∴(a+b)²=0
∴a+b=0

a(a+4b)-(a+2b)(a-2b)
=a²+4ab-a²+4b²
=4b(a+b)
=0

Answer 3

等于0