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(1)f'(x)=-sinx-xcosx
f"(x)=-cosx-cosx+xsinx=-2cosx+xsinx
f"(0)=-2
(2)lim(x→0)(e^x+sinx-1)/ln(1+x) (ln(1+x)~x)
=lim(x→0)(e^x+sinx-1)/x (这是0/0型,运用洛必达法则)
=lim(x→0)(e^x+cosx)/1
=2
f"(x)=-cosx-cosx+xsinx=-2cosx+xsinx
f"(0)=-2
(2)lim(x→0)(e^x+sinx-1)/ln(1+x) (ln(1+x)~x)
=lim(x→0)(e^x+sinx-1)/x (这是0/0型,运用洛必达法则)
=lim(x→0)(e^x+cosx)/1
=2
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