Question

若-2ax3y│n-1│是关于x,y的单项式，且系数是8，次数是5，（1）求a和n

Answer 1

-2a=8

3+│n-1│=5

a=-4
n-1=±2
n=3或-1

Answer 2

- 2 a x³ y^|n-1| 系数是8，次数是5
=> - 2a = 8, 3 + |n-1| = 5
=> a = -4, n= -1 或 n =3