Question

求s2/1+3/2+4/3+5/4+...22/21的值 c语言

急！！！考试中
求s=2/1+3/2+4/3+5/4+...22/21的值 c语言

Answer 1

int i = 0;
double s = 0.0;

for (i = 1; i < 22; i++)
{
s = (double)(i+1) / (double)i;
}

printf("s=%f", s);

记住在做(i+1)/i之前要把它们先强制类型转换成double型，否则精度会有问题。

Answer 2

double s;
int i;
s=0;
for (i=1; i<=21; i++)
s+=(i+1)/i;
printf ("s=%.06f\n\n", s);

Answer 3

int main(void)
{
double s=0;
int i;
for (i=1; i<=21; i++)
{
s+=1.0*(i+1)/i;
}
printf ("s=%f\n\n", s);
return 0;
}