
已知函数f(x)=3sin(x/2+π/6)用五点画图法画出它在一个周期内的图象
1个回答
展开全部
T=2π/0.5=4π
f(x)=3sin[0.5(x+π/3)]
f(x)=0,0.5(x+π/3)=0; 0.5(x+π/3)=π,0.5(x+π/3)=2π;
x=-π/3; x=5π/3; x=11π/3
f(x)=1,0.5(x+π/3)=π/2
x=2π/3;
f(x)=-1,0.5(x+π/3)=3π/2
x=8π/3
五点连接
f(x)=3sin[0.5(x+π/3)]
f(x)=0,0.5(x+π/3)=0; 0.5(x+π/3)=π,0.5(x+π/3)=2π;
x=-π/3; x=5π/3; x=11π/3
f(x)=1,0.5(x+π/3)=π/2
x=2π/3;
f(x)=-1,0.5(x+π/3)=3π/2
x=8π/3
五点连接
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询