高数 求导数?
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y= [x(x^3+1)/(x-1)^2]^(1/3)
lny = (1/3) [ lnx +ln(x^3+1) - 2ln(x-1) ]
y'/y =(1/3) [1/x + 3x^2/(x^3+1) - 2/(x-1) ]
y' =(1/3) [1/x + 3x^2/(x^3+1) - 2/(x-1) ] . [x(x^3+1)/(x-1)^2]^(1/3)
lny = (1/3) [ lnx +ln(x^3+1) - 2ln(x-1) ]
y'/y =(1/3) [1/x + 3x^2/(x^3+1) - 2/(x-1) ]
y' =(1/3) [1/x + 3x^2/(x^3+1) - 2/(x-1) ] . [x(x^3+1)/(x-1)^2]^(1/3)
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