
2011-10-25 · 知道合伙人教育行家
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1.(x-3)²=-2(x-3)
(x-3)²+2(x-3)=0
(x-3)(x-3+2)=0
(x-3)(x-1)=0
x1=1
x2=3
2.x²-3=2根号2x
x²-2根号2x=3
(x-√2)^2 = 3+2 = 5
x-√2 = ±√5
x1=√2 -√5
x2=√2 +√5
3.4(x-3)²-25(x-2)²=0
(2x-6)²-(5x-10)²=0
(2x-6+5x-10)(2x-6-5x+10)=0
(7x-16)(-3x+4)=0
x1=16/7
x2=4/3
(x-3)²+2(x-3)=0
(x-3)(x-3+2)=0
(x-3)(x-1)=0
x1=1
x2=3
2.x²-3=2根号2x
x²-2根号2x=3
(x-√2)^2 = 3+2 = 5
x-√2 = ±√5
x1=√2 -√5
x2=√2 +√5
3.4(x-3)²-25(x-2)²=0
(2x-6)²-(5x-10)²=0
(2x-6+5x-10)(2x-6-5x+10)=0
(7x-16)(-3x+4)=0
x1=16/7
x2=4/3
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