Question

根号x-y+3与根号x+y-1互为相反数求x+y

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Answer 1

√(x-y+3)与√(x+y-1)互为相反数求x+y
解：因为√(x-y+3)与√(x+y-1)互为相反数，∴√(x-y+3)+√(x+y-1)=0；而√(x-y+3)与√(x+y-1)都是非
负数，两个非负数之和为零，那只有两个数都是零才有可能，故必有：
x-y+3=0.........(1)
x+y-1=0.........(2)
(1)+(2)得2x+2=0，故x=-1，代入(1)式即得y=2，故x+y=-1+2=1 .

Answer 2

x-y+3=x+y-1=0
=>x+y=1

Answer 3

由题意知x-y+3=0
x+y-1=0
解得x=-1，y=2
x+y=1

追问

详细点+解释我很笨

追答

算术平方根非负，两个非负数相加为0，只能它们分别为0，所以根号下的数都为0

Answer 4

x+y=1