Question

（x+2)的平方=3x+6 (3x+2)的平方-4x的平方=0 5(2x-1)=(1-2x)(x+3) 2(x-3)+(3x-x的平方)

急 快一点
用因式分解法

Answer 1

（x+2)的平方=3x+6
(x+2)²-3(x+2)=0
(x+2)(x+2-3)=0
x+2=0 x-1=0
∴X1=-2
X2=1

(3x+2)的平方-4x的平方=0
(3X+2-2X)(3X+2+2X)=0
(X+2)(5X+2)=0
X+2=0 5X+2=0
∴X1=-2
X2=-2/5

5(2x-1)=(1-2x)(x+3)
5(2X-1)-(1-2X)(X+3)=0
(2X-1)(5+X+3)=0
2X-1=0 X+8=0
∴X1=1/2
X2=-8

2(x-3)+(3x-x的平方)=0
2(X-3)-x(x-3)=0
(x-3)(2-x)=0
x-3 =0 2-x=0
∴X1=3
X2=2

Answer 2

(x+2)²=3x+6
(x+2)²-(3x+6)=0
(x+2)²-3(x+2)=0
(x+2)(x+2-3)=0
(x+2)(x-1)=0
x=-2或x=1

(3x+2)²-4x²=0
[(3x+2)-2x][(3x+2)+2x]=0
(3x+2-2x)(3x+2+2x)=0
(x+2)(5x+2)=0
x=-2或x=-2/5

5(2x-1)=(1-2x)(x+3)
5(2x-1)-(1-2x)(x+3) =0
5(2x-1)+(2x-1)(x+3) =0
(2x-1)(5+x+3) =0
(2x-1)(x+8)=0
x=1/2或x=-8