Question

php中，怎样在文本框里输入字母，然后根据字母在数据库中模糊查询所有首字母为文本框输入的字母的值

根据“A”查询数据库中所有汉字首字母为“A”的数据

Answer 1

<?php
include('Common/db.php'); //数据库连接类
$db=new DB();
$shouzimu=strtoupper("r"); //传过来的参数
$arr=$db->get_all("SELECT * FROM [user]");
foreach($arr as $rs){
$panduan=ff_letter_first($rs['uname']);//调用下面的方法
if($panduan==$shouzimu){
print_r($rs);
}

}

//生成字母前缀
function ff_letter_first($s0){
$firstchar_ord=ord(strtoupper($s0{0}));
if (($firstchar_ord>=65 and $firstchar_ord<=91)or($firstchar_ord>=48 and $firstchar_ord<=57)) return $s0{0};
$s=iconv("UTF-8","gb2312", $s0);
$asc=ord($s{0})*256+ord($s{1})-65536;
if($asc>=-20319 and $asc<=-20284)return "A";
if($asc>=-20283 and $asc<=-19776)return "B";
if($asc>=-19775 and $asc<=-19219)return "C";
if($asc>=-19218 and $asc<=-18711)return "D";
if($asc>=-18710 and $asc<=-18527)return "E";
if($asc>=-18526 and $asc<=-18240)return "F";
if($asc>=-18239 and $asc<=-17923)return "G";
if($asc>=-17922 and $asc<=-17418)return "H";
if($asc>=-17417 and $asc<=-16475)return "J";
if($asc>=-16474 and $asc<=-16213)return "K";
if($asc>=-16212 and $asc<=-15641)return "L";
if($asc>=-15640 and $asc<=-15166)return "M";
if($asc>=-15165 and $asc<=-14923)return "N";
if($asc>=-14922 and $asc<=-14915)return "O";
if($asc>=-14914 and $asc<=-14631)return "P";
if($asc>=-14630 and $asc<=-14150)return "Q";
if($asc>=-14149 and $asc<=-14091)return "R";
if($asc>=-14090 and $asc<=-13319)return "S";
if($asc>=-13318 and $asc<=-12839)return "T";
if($asc>=-12838 and $asc<=-12557)return "W";
if($asc>=-12556 and $asc<=-11848)return "X";
if($asc>=-11847 and $asc<=-11056)return "Y";
if($asc>=-11055 and $asc<=-10247)return "Z";
return 0;//null
}

?>

Answer 2

建立个首字母字段，查询首字母字段

追问

还有别的方法么，比如说不用动数据表可以用代码直接处理么

Answer 3

select * from table where username like 'A%'

追问

可能我表答的不是很准确，查询的不是“A”开头的字，而是首字母以“A”开头的字