Question

java,任意输入一串数字，要求算出最大值最小值。 请用最简单的方法

Enter a number (a non-number to exit): 2
Enter a number (a non-number to exit): 4
Enter a number (a non-number to exit): 8
Enter a number (a non-number to exit): -2
Enter a number (a non-number to exit): -4
Enter a number (a non-number to exit): -3
Enter a number (a non-number to exit): x
Max of the numbers: 8
Min of the numbers: -3

Answer 1

设置两个变量 max min
输入的时候就比较一下,然后获取对应的max 和 min
最后的结果就出来了

如:int max=0,min=0

int sr=new Integer(输入);
if(sr>max)max=sr;
if(sr<min)min=sr;

Answer 2

import java.util.Scanner;

public class Number {

public static void main(String[] args) {

String input = null;

Scanner scanner = new Scanner(System.in);
int max = 0;
int min = 0;

boolean isFirst = true;

while(true){
System.out.print("Enter a number (a non-number to exit): ");

input = scanner.next();

try{
int value = Integer.parseInt(input);

if(isFirst){
max = value;
min = value;
isFirst = false;
}else{
if(value > max){
max = value;
}else{
min = value;
}
}

}catch(NumberFormatException exp){
System.out.println("Max of the numbers : " + max);
System.out.println("Min of the numbers : " + min);
break;
}

}

}

}

--------------testing
Enter a number (a non-number to exit): 2
Enter a number (a non-number to exit): 4
Enter a number (a non-number to exit): 8
Enter a number (a non-number to exit): -2
Enter a number (a non-number to exit): -4
Enter a number (a non-number to exit): -3
Enter a number (a non-number to exit): x
Max of the numbers : 8
Min of the numbers : -3

Answer 3

写一个求最值的函数即可