
已知向量a,b的夹角为120° /a/=1,/b/=3,则/5a-b/=?
2个回答
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|5a-b|^2
= (5a-b).(5a-b)
= 25|a|^2 +|b|^2-10|a||b|cos120°
= 25+9 +10(1)(3)(1/2)
= 34+15
=49
|5a-b| =7
= (5a-b).(5a-b)
= 25|a|^2 +|b|^2-10|a||b|cos120°
= 25+9 +10(1)(3)(1/2)
= 34+15
=49
|5a-b| =7
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