Question

数学 急急急 转换

请写出公式，谢谢，过程要详细

Answer 1

sin(-π-π/3)
=sin(-4π/3)
sinx的周期为2π，所以
sin(-4π/3)=sin(-4π/3+2π)=sin(2π/3)
又sinx沿x=π/2对称，所以
sin(2π/3)=sin(π/3)=sin(-4π/3)

Answer 2

答：三角函数公式：sin（-x）=-sinx，sin（Π+x）=-sinx，所以sin（-Π-Π/3）=sin[-(Π+Π/3）]=-sin(Π+Π/3）=sinΠ/3

Answer 3

提取负号：=sin[-(π + π/3)]
由诱导公式sin(-α)=-sinα得：
=-sin(π + π/3)
再由诱导公式sin(π+α)=-sinα得：
=-[-sin(π/3)]
负负得正：=sin(π/3)

Answer 4

sin(-兀-兀/3)
=sin(-4兀/3)
=-sin4兀/3
=-(-sin兀/3)
=sin兀/3
=√3/2

Answer 5

sin(-π-π/3)=sin(2π-π-π/3)=sin(π-π/3)=sin(π/3)=√3/2