Question

把下列格式分母有理化.(1)3√2/4√5 (2)√9a/√2 (3)√2.√6/√3 (4)√x+y/2 (x+y＞0）

过程 答对继续加分

Answer 1

3√2/4√5
=3√2*√5/(4√5*√5)
=3√10/20

√9a/√2
=3√a/√2
=3√a*√2/(√2*√2)
=3√2a/2

√2*√6/√3
=√2*√2*√3/√3
=√2*√2
=2

√[(x+y)/2]
= √[2(x+y)/(2*2)]
= √(2x+2y)/2

Answer 2

(1)3√2/4√5 =3/20√10
(2)√9a/√2=3/2√ 2a
(3)√2.√6/√3=√4=2
(4)√x+y/2 (x+y＞0）=1/2√2x+y

Answer 3

(1)3√2/4√5=3√2√5/4√5√5=3√10/20
(2)√9a/√2 =√9a√2 /√2 √2 =3√2a/4
(3)√2.√6/√3=√2.√6√3/√3√3=2
(4)√x+y/2 (x+y＞0）题目没看明白