分式加减： 2除以（a+1） - （a^-1）分之（a-2） 除以 【a^2-2a+1分之a^2-2a】
分式加减： 2除以（a+1） - （a^-1）分之（a-2） 除以 【a^2-2a+1分之a^2-2a】
2/(a+1)-(a-2)/(a²-1)÷[(a²-2a)/(a²-2a+1)]
=2/(a+1)-(a-2)/[(a+1)(a-1)]× (a-1)²/[a(a-2)]
=2/(a+1)-1/(a+1)× (a-1)/a
=2/(a+1)-(a-1)/[a(a+1)]
=2a/[a(a+1)-(a-1)/[a(a+1)]
=[2a-(a-1)]/[a(a+1)]
=(a+1)/[a(a+1)]
=1/a
2013a除以(a的2次方-2a+1)除以((a的2次方-1分之a+1)+1)分式化简
2013a/(a²-2a+1)÷(a+1)/(a²-1)+1
=2013a/(a-1)²×(a-1)(a+1)/(a+1)+1
=2013a/(a-1)×(a+1)/(a+1)+1
=2013a+a-1/(a-1)
=(2014a-1)/(a-1)
有没有错？
化简(1+a-2分之4)除以a-2分之a
原式=[(a-2)/(a-2)+4/(a-2)]÷a/(a-2)
=(a+2)/(a-2)×(a-2)/a
=(a+2)/a
先化简，再计算：（a-2分之1加a2-a-2分之a2-1）除以（a-2分之a）= ，当a=3是，原式= 、
解：[1/(a-2) + (a²-1)/(a²-a-2)] ÷ a/(a-2)
=(a+1+a²-1)/[(a+1)(a-2)] × (a-2)/a
=a(a+1)/(a+1) × (1/a)
=1
所以当a＝3时，原式＝1
x的平方减1分之2x减2除以（1减x加1分之1）
解：
原式=[(2x-2)/(x²-1)]÷[1-1/(x+1)]
={2(x-1)/[(x-1)(x+1)]}÷[(x+1)/(x+1)-1/(x+1)]
=[2/(x+1)]÷[x/(x+1)]
=[2/(x+1)]×[(x+1)/x]
=2/x
-1的2012次幂-12除以2*2分之1+（-2）的3次幂除以（-2分之1）
=1-12-8*（-2）
=1-12+16
=5
3分之1除以4加2分之1=
3分之1÷4+2分之1
=3分之1×4分之1+2分之1
=12分之1+2分之1
=12分之1+12分之6
=12分之7
[（a^2+2a分之a-2）-（a^2+4a+4分之a-1）]除以a+2分之a-4，其中a=-3
[（a^2+2a分之a-2）-（a^2+4a+4分之a-1）]除以a+2分之a-4，其中a=-3
=[(a-2)/a(a+2)-(a-1)/(a+2)²]÷(a-4)/(a+2)
=[(a²-4-a²+a)/a(a+2)²]*(a+2)/(a-4)
=[(a-4)/a(a+2)²]*(a+2)/(a-4)
=1/a(a+2)
=1/(-3)(-3+2)
=1/3
（【2a-2分之a+1】-【2a的平方-2分之5】-【2a+2分之a+3】）除以【4a-4分之3】，其中a=—2分之1
[(a+1)/(2a-2) -5/(2a²-2) -(a+3)/(2a+2)]÷[3/(4a-4)]
=[(a+2)/(2(a-1)) -5/[2(a+1)(a-1) -(a+3)/(2(a+1)]/[3/(4(a-1))]
=[(a+2)(a+1)-5-(a+3)(a-1)]/[2(a+1)(a-1)]/[3/(4(a-1))]
=[(a²+3a+2-5-a²-2a+3)/(2(a+1)(a-1))]/[3/(4(a-1))]
=[a/[2(a+1)(a-1)]]/[3/4(a-1)]
=4a(a-1)/[6(a+1)(a-1)]
=2a/[3(a+1)]
=2(-1/2)/[3(-1/2+1)]
=(-1)/(3/2)
=-2/3
负2除以2分之1=?
负4
